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24x^2+112=184x
We move all terms to the left:
24x^2+112-(184x)=0
a = 24; b = -184; c = +112;
Δ = b2-4ac
Δ = -1842-4·24·112
Δ = 23104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{23104}=152$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-184)-152}{2*24}=\frac{32}{48} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-184)+152}{2*24}=\frac{336}{48} =7 $
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